This topic has 1 reply, 1 voice, and was last updated 4 months ago by .Viewing 2 posts - 1 through 2 (of 2 total)AuthorPosts November 11, 2024 at 8:55 am #3072 Frage: (st-36) ⓘ 🖶 ausdrucken [klick Frage/Antwort] ◀ – ▶ Zu 300 ml einer Lösung mit c = 0.3 mol/l werden 200 ml einer (gleichen) Lösung mit c= 0.5 mol/L gegeben. Welche Konzentration hat die Lösung jetzt? November 11, 2024 at 8:55 am #3073 Textantwort: c = n/V resp. n = c·V n1(Lösung) = c1·V1 = 0.3 mol/l·0.3 l = 0.09 mol n2(Lösung) = c2·V2 = 0.5 mol/l·0.2 l = 0.1 mol neue n: n1 + n2 = 0.19 mol neues Volumen: 300 ml + 200 ml = 500 ml rsp. 0.55 L c = n/V = 0.19 mol / 0.5 L = 0.38 mol/LAuthorPostsViewing 2 posts - 1 through 2 (of 2 total)You must be logged in to reply to this topic.Log In Username: Password: Keep me signed in Log In Log in / Register