This topic has 1 reply, 1 voice, and was last updated 2 weeks, 6 days ago by .Viewing 2 posts - 1 through 2 (of 2 total)AuthorPosts March 31, 2025 at 7:14 am #3360 Frage: (thermo-102) ⓘ 🖶 ausdrucken [klick Frage/Antwort] ◀ – ▶ Beim Umsatz von 60 Gramm Traubenzucker werden x kJ frei. Berechne daraus die ΔHof. March 31, 2025 at 7:14 am #3361 Textantwort: M(Traubenzucker) = M(C6H12O6) = 180 Gramm Mit 60 g C6H12O6 x kJ, bei einem Mol (=180 g) somit 3·x. ΔHof(C6H12O6) = 3·x kJ/mol.AuthorPostsViewing 2 posts - 1 through 2 (of 2 total)You must be logged in to reply to this topic.Log In Username: Password: Keep me signed in Log In Log in / Register