This topic has 1 reply, 1 voice, and was last updated 4 months ago by .Viewing 2 posts - 1 through 2 (of 2 total)AuthorPosts November 11, 2024 at 8:57 am #3340 Frage: (thermo-106) ⓘ 🖶 ausdrucken [klick Frage/Antwort] ◀ – ▶ Berechne die ΔHof von Kohlenmonoxid. Betrachte dazu folgende Reaktion: CH4(g) + H2O(l) → CO(g) + 3 H2(g). Die (experimentelle) ΔHoR hierfür betrage 249.5 kJ/mol. November 11, 2024 at 8:57 am #3341 Textantwort: ΔHoR = [ ΔHof(CO(g)) + 3· ΔHof(H2(g))] – [ ΔHof(CH4) + ΔHof(H2O(l))] ΔHoR = 249.5 kJ/mol = [x + 3·0]-[-74.85 + -285.83] x = …AuthorPostsViewing 2 posts - 1 through 2 (of 2 total)You must be logged in to reply to this topic.Log In Username: Password: Keep me signed in Log In Log in / Register